Question

What is the equation of the line between `(3,-13)` and `(5,1)`?

Answer 1

`s =((-2 lambda+5),(-14 lambda+1))` for `0 le lambda le 1`

Explanation:

Given two points `p_1,p_2` the segment `s` they define is given by

`s = lambda p_1+(1-lambda)p_2` for `0 le lambda le 1`
`s = lambda(3,-13)+(1-lambda)(5,1) = ((3 lambda +5(1-lambda)),(-13 lambda +1(1-lambda)))`