Question

What is the equation of the line between `(-3,-3)` and `(-4,1)`?

Answer 1

Equation of the line is `4x+y+15=0`

Explanation:

Equation of a line joining two points `(x_1,y_1)` and `(x_2,y_2)` is given by

`(x-x_1)/(x_2-x_1)=(y-y_1)/(y_2-y_1)`

Hence equation of line joining `(-3,-3)` and `(-4,1)` is

`(x-(-3))/((-4)-(-3))=(y-(-3))/(1-(-3))`

or `(x+3)/((-4+3))=(y+3)/(1+3)`

or `(x+3)/(-1)=(y+3)/4`

or `4(x+3)=-y-3`

or `4x+y+12+3=0` or `4x+y+15=0`