What is the equation of the line passes through (2,3) and (-2,1)?

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What is the equation of the line passes through (2,3) and (-2,1)?

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Answer 1 · 2018-03-08T05:02:25

$y = \frac{1}{2} x + 2$ $y=1/2x+2$

Explanation:

First, I would want to find the slope of the line. For this, you would do the change in y over the change in x
$\frac{Y_{2} - Y_{1}}{X_{2} - X_{1}} =$ $(Y_2-Y_1) / (X_2-X_1)=$

$\frac{3 - 1}{2 - (- 2)} =$ $(3-1 )/ (2-(-2))=$

$\frac{2}{4} = \frac{1}{2}$ $2 / 4 = 1/2$
.5 this means that the slope is .5 or 1/2

Then, you need to find the y intercept, by using point-slope form
$y - y_{1} = m (x - x_{1})$ $y-y_1=m(x-x_1)$
$y - 3 = \frac{1}{2} (x - 2)$ $y-3=1/2(x-2)$
$y - 3 = \frac{1}{2} x - 1$ $y-3=1/2x-1$
$y = \frac{1}{2} x + 2$ $y=1/2x+2$

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What is the equation of the line passes through (2,3) and (-2,1)?

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