What is the equation of the line passing through (13,-4)(13,4) and (14,-9)(14,9)?

2 Answers
Dec 23, 2017

y + 4 = -5(x-13)y+4=5(x13)

Explanation:

I'm not sure which form of equation you want it to be in, but going to show the simplest, or point-slope form, which is y - y_1 = m(x-x_1)yy1=m(xx1).

First, we need to find the slope of the line, mm.

To find the slope, we use the formula m = (y_2-y_1)/(x_2-x_1)m=y2y1x2x1, also known as "rise over run", or change of yy over change of xx.

Our two coordinates are (13, -4)(13,4) and (14, -9)(14,9). So let's plug those values into the slope equation and solve:
m = (-9-(-4))/(14-13)m=9(4)1413
m = -5/1m=51
m = -5m=5

Now, we need a set of coordinates from the given or the graph. Let's use the point (13, -4)(13,4)

So our equation is:
y-(-4) = -5(x-13)y(4)=5(x13)

Simplified...
y + 4 = -5(x-13)y+4=5(x13)

Dec 23, 2017

y=-5x+61y=5x+61

Explanation:

"the equation of a line in "color(blue)"slope-intercept form"the equation of a line in slope-intercept form is.

•color(white)(x)y=mx+bxy=mx+b

"where m is the slope and b the y-intercept"where m is the slope and b the y-intercept

"to calculate m use the "color(blue)"gradient formula"to calculate m use the gradient formula

color(red)(bar(ul(|color(white)(2/2)color(black)(m=(y_1-y_1)/(x_2-x_1))color(white)(2/2)|)))

"let "(x_1,y_1)=(13,-4)" and "(x_2,y_2)=(14-9)

rArrm=(-9-(-4))/(14-13)=-5

rArry=-5x+blarrcolor(blue)"is the partial equation"

"to find b use either of the two given points"

"using "(13,-4)

-4=-65+brArrb=61

rArry=-5x+61larrcolor(red)"in slope-intercept form"