What is the equation of the line passing through $(13, 7)$ $(13,7)$ and $(19, 19)$ $(19,19)$ ?

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Answer 1 · 2016-04-11T10:27:47

$2 x - y = 19$ $2x-y=19$

The equation of a line passing through two points $(x_{1}, y_{1})$ $(x_1,y_1)$ and $(x_{2}, y_{2})$ $(x_2,y_2)$ is given by

$\frac{y - y_{1}}{y_{2} - y_{1}} = \frac{x - x_{1}}{x_{2} - x_{1}}$ $(y-y_1)/(y_2-y_1)=(x-x_1)/(x_2-x_1)$

Hence equation of line passing through $(13, 7)$ $(13,7)$ and $(19, 19)$ $(19,19)$ is

$\frac{y - 7}{19 - 7} = \frac{x - 13}{19 - 13}$ $(y-7)/(19-7)=(x-13)/(19-13)$ or

$\frac{y - 7}{12} = \frac{x - 13}{6}$ $(y-7)/12=(x-13)/6$ or $\frac{y - 7}{2} = (x - 13)$ $(y-7)/2=(x-13)$

or $(y - 7) = 2 (x - 13)$ $(y-7)=2(x-13)$ or

$y - 7 = 2 x - 26$ $y-7=2x-26$ i.e.

$2 x - y = 19$ $2x-y=19$

What is the equation of the line passing through (13,7)(13,7)(13,7) and (19,19)(19,19)(19,19)?