What is the equation of the line passing through (3,-4) and (-5,-1)?

1 Answer
Dec 18, 2016

4x + 8y + 20 = 0

Explanation:

we know equation of a line passing through (x_1,y_1) and (x_2, y_2)

= [y-y_1]/[x-x_1] = [y_2-y_1]/[x_2-x_1]

So equation of line passing through (3, -4) and (-5, -1) =

[y-(-4)]/[x-3] = [-1-(-4)]/[-5-3]

or, [y+4]/[x-3] = [-1+5]/[-8]

or, -8(y+4) = 4(x-3)

or,-8y-32 = 4x-12

or, 4x + 8y + 32 - 12 = 0

or, 4x + 8y + 20 = 0