What is the equation of the line passing through $(5, 4)$ $(5,4)$ and $(- 9, - 2)$ $(-9,-2)$ ?

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Answer 1 · 2016-06-09T09:39:11

The equation of the straight line is : $7 y - 3 x + 11 = 0$ $7y - 3x + 11 =0$

Let $A (x 1, y 1) = A (5, 4)$ $A(x1,y1) = A(5,4)$
and $B (x 2, y 2) = B (- 9, - 2)$ $B(x2,y2) = B(-9,-2)$

First find the slope of the line, using the formula :

$m = \frac{y 2 - y 1}{x 2 - x 1}$ $m = (y2-y1)/(x2-x1)$

$m = \frac{- 6}{- 14} = \frac{3}{7}$ $m = (-6)/-14 = 3/7$

Now using the point-slope form of a straight line :
$y - y 1 = m (x - x 1)$ $y-y1=m(x-x1)$

$y - 4 = \frac{3}{7} \cdot (x - 5)$ $y-4=3/7*(x-5)$

On simplifying, we get,
$7 y - 3 x + 11 = 0$ $7y - 3x + 11 =0$

graph{3/7*(x-5) +4 [-10, 10, -5, 5]}

What is the equation of the line passing through (5,4)(5,4)(5,4) and (-9,-2)(−9,−2)(-9,-2)?