What is the equation of the line through points (-2, 5) and (3, 5)?

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Answer 1 · 2018-03-25T19:07:19

The equation of the line is $y = 5$ $y=5$

If $A (x_{1}, y_{1}) and B (x_{2}, y_{2})$ $A(x_1,y_1) and B(x_2,y_2)$ ,then equation of the line:

$\frac{x - x_{1}}{x_{2} - x_{1}} = \frac{y - y_{1}}{y_{2} - y_{1}}$ $color(red)((x-x_1)/(x_2-x_1)=(y-y_1)/(y_2-y_1)$ .

But we have,

$A (- 2, 5) and B (3, 5)$ $A(-2,5) and B(3,5)$

Here, $y_{1} = y_{2} = 5$ $y_1=y_2=5$

$\Rightarrow$ $=>$ The line is horizontal and perpendicular to Y-axe.

So ,the equation of the line is $y = 5$ $y=5$
graph{0x+y=5 [-20, 20, -10, 10]}