What is the equation of the perpendicular bisector of a chord of a circle?
2 Answers
For a chord AB, with
Explanation:
Supposing a chord AB with
The midpoint is
The slope of the segment defined by A and B (the chord) is
The slope of the line perpendicular to the segment AB is
The equation of the line required is
#y-y_M=p(x-x_M)#
#y-(y_A+y_B)/2=-(x_B-x_A)/(y_B-y_A)*(x-(x_A+x_B)/2)#
Or
#y=-(x_B-x_A)/(y_B-y_A)*(x-(x_A+x_B)/2)+(y_A+y_B)/2#
Note: the center of the circle, assummedly point C
The equation of the perpendicular bisector of a chord of a circle is the equation of a diameter of the circle.
Explanation:
Let the equation of the circle be standard one having center at origin and radius r
The coordinates of the end points of the chord AB
The coordinate of the middle point C (x',y') of AB
The slope of AB
Slope of the perpendicular bisector of AB is
The equation of the perpendicular bisector of AB
OR
Obviously this is the equation of a straight line passing through the origin (0,0),the center of the circle. So the perpendicular bisector of the chord is a diameter of the circle.