What is the excluded value of $\frac{2 x - 1}{{(x - 1)}^{2}}$ $\frac{2x-1}{(x-1)^2}$ ?

Question

What is the excluded value of $\frac{2 x - 1}{{(x - 1)}^{2}}$ $\frac{2x-1}{(x-1)^2}$ ?

1 Answer

Impact of this question

8971 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2014-12-18T18:17:08

$x = 1$ $x=1$

You can't divide by zero, so that would be the x-value for which the denominator is equal to zero.
${(x - 1)}^{2} = 0$ $(x-1)^2=0$ if and only if $(x - 1) = 0$ $(x-1)=0$ , so $x = 1$ $x=1$ .

Science

Math

Humanities

... and beyond

What is the excluded value of $\frac{2 x - 1}{{(x - 1)}^{2}}$ $\frac{2x-1}{(x-1)^2}$ ?

1 Answer

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

What is the excluded value of \frac{2x-1}{(x-1)^2}2x−1(x−1)2\frac{2x-1}{(x-1)^2}?

1 Answer

Related questions

Impact of this question

What is the excluded value of $\frac{2 x - 1}{{(x - 1)}^{2}}$ $\frac{2x-1}{(x-1)^2}$ ?