What is the focus of the parabola #(y-9)^2 = -8(x+5)#?

1 Answer
May 27, 2017

Focus is at # (-7,-9)#

Explanation:

#(y-9)^2 = -8 (x+5) or (y-9)^2 = -4 *2 (x+5) ; h= -5 , k =9 , a = -2# .

This is a parabola of standard equation # (y-k)^2 = -4a (x-h) # opening left .

Vertex is at #(h,k) i.e ( -5,9) # . Focus is at "#a#" distance left of vertex.

So focus is at #(h+a),k or ( (-5-2), 9) or (-7,9) #
graph{(y-9)^2=-8(x+5) [-80, 80, -40, 40]} [Ans]