What is the gram-formula mass of (NH_4)_3PO_4(NH4)3PO4?

1 Answer
Meave60
Jul 10, 2018

It is "149.087 g/mol"149.087 g/mol.

Explanation:

Multiply the subscript for each element by its molar mass, which is its atomic weight in g/mol. In the case of ("NH"_4)_3"(NH4)3, multiply the subscripts inside the parentheses by 33.

Gram-formula mass of ("NH"_4)_3"PO"_4"(NH4)3PO4

(3xx"14.007 g/mol N") + (12xx"1.008 g/mol H") + (1xx"30.974 g/mol P") + (4xx"15.999 g/mol O")=(3×14.007 g/mol N)+(12×1.008 g/mol H)+(1×30.974 g/mol P)+(4×15.999 g/mol O)=

"149.087 g/mol"149.087 g/mol ("NH"_4)_3"PO"_4"(NH4)3PO4

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