What is the integral of $xe^x$ from -infinity to 0?

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Answer 1 · 2015-07-14T16:24:33

I found: $int_(-oo)^0xe^xdx=-1$

I would solve it by parts:
$intxe^xdx=xe^x-int1*e^xdx=xe^x-e^x=$
using your extrema:
$=e^x(x-1)|_-oo^0$ $=$
$=-1-0=-1$

[where I used the fact that: $e^0=1 and e^-oo=1/e^oo=0$ ]

What is the integral of xe^xxe^x from -infinity to 0?