Question

What is the inverse of `f(x)= -log_5 (x-3)` ?

Answer 1

`f^-1=1/5^x+3`

Explanation:

`y=-log_5(x-3)`
`=>log_5(x-3)=-y`
`=>x-3=5^-y`
`=>x=1/5^y+3`
`=>f^-1=1/5^x+3`