What is the inverse of $log (x^2/2)-3log(x)$ ?

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Answer 1 · 2016-03-26T15:02:27

$x= 10^(-y)/2$ , , where y is the given function.

Let $y=log(x^2/2)-3 log(x)$

= $log ( x^2)+log(x^(-3))+log (2^(-1))$

= $log ((2x)^(-1))$ .

Inversely, $(2x)^(-1)=10^y$ . So, $x= 10^(-y)/2$

What is the inverse of log (x^2/2)-3log(x)log (x^2/2)-3log(x) ?