What is the ion-product constant, Kw?

1 Answer
Jun 11, 2017

For water, this is the measure of the autoprotolysis reaction....

Explanation:

2H2O(l)H3O++HO

And Kw=[HO][H3O+]=1014 at 298K.

And when we take log10 of both sides we get the useful expression...........

pH+pOH=14, where pH=log10[H3O+] etc.

How do you think Kw would develop if non-standard conditions pertained; e.g. if temperature was say 373K. Would Kw remain constant, decrease, increase? Remember that the autoprotolysis reaction as shown is a bond-breaking reaction.