What is the lewis structure for $SO_4$ with 2- charge?

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Answer 1 · 2016-06-11T05:41:56

This is the tetrahedral sulfate ion, $SO_4^(2-)$

$=$ $6(S) + 4xx6(O) + 2e^(-)=32" electrons"$ , to be distributed across 5 centres, with a central $S$ atom.

$S(=O)_2(-O^-)_2$ , i.e. 16 electron pairs distributed around the 5 centres.

In the actual molecule, all the oxygen atoms are equivalent.

The sulfate ion derives from sulfuric acid, $H_2SO_4$ , i.e.
$S(=O)_2(-OH)_2$ . The oxidation state of sulfur here is $VI+$ .

What is the lewis structure for SO_4SO_4 with 2- charge?