What is the Lewis structure of $O C S$ $OCS$ ?

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What is the Lewis structure of $O C S$ $OCS$ ?

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Answer 1 · 2016-08-04T23:05:12

If you think about it, $S$ $"S"$ is right below $O$ $"O"$ , so the number of valence electrons it contributes is the same.

Therefore, $OCS$ $"OCS"$ is isoelectronic with ${CO}_{2}$ $"CO"_2$ , having the same number of valence electrons but not identical atoms.

So, what you have in comparison is:

$: . . O = C = . . S :$ $color(blue)( :stackrel(..)"O"="C"=stackrel(..)"S": )$ $\Rightarrow$ $=>$ $OCS$ $"OCS"$

$: . . O = C = . . O :$ $:stackrel(..)"O"="C"=stackrel(..)"O":$ $\Rightarrow$ $=>$ ${CO}_{2}$ $"CO"_2$

You can do the electron-counting method and get the same result.

$O : 6$ $"O": 6$
$C : 4$ $"C": 4$
$S : 6$ $"S": 6$

$6 + 4 + 6 = 16$ $6+4+6 = 16$ valence electrons

Distribute $8$ $8$ of them in two double bonds ( $2$ $2$ per bond line), and you have $8$ $8$ remaining.

$O = C = S$ $"O"="C"="S"$

So, $4$ $4$ as lone pairs on $O$ $"O"$ and $4$ $4$ as lone pairs on $S$ $"S"$ . This also gives you the above result.

$: . . O = C = . . S :$ $:stackrel(..)"O"="C"=stackrel(..)"S":$

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What is the Lewis structure of $O C S$ $OCS$ ?

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What is the Lewis structure of OCSOCS?

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What is the Lewis structure of $O C S$ $OCS$ ?