What is the mass of 7.83 * 10^23 atoms Cl?

1 Answer
anor277
Nov 29, 2015

Slightly over 35.5 grams.

Explanation:

If I have Avogadro's number of chlorine atoms, I necessarily have 35.45 g chlorine.

Here we have a number that is in excess of Avogadro's number, 6.022xx10^(23) = N_A.

Since I know that if I have 6.022xx10^(23) atoms of chlorine I have a mass of 35.45 g of chlorine, then all I have to do is give the product, 35.45*g xx(7.83xx10^(23))/(6.022xx10^(23)) = ?? g.

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