What is the minimum or maximum of f(x)=-2x^2+7x-3?

1 Answer
Aug 6, 2015

What is the max or Min of f(x) = - 2x^2 + 7x - 3

Ans: Max at vertex (7/4, 1/16)

Explanation:

Since a < 0, the parabola opens downward, there is a max at the vertex.
x-coordinate of vertex: x = -b/(2a) = -7/-4 = 7/4
y-coordinate of vertex: y = f(7/4) = - 49/16 + 49/4 - 3 =

= 49/16 - 48/16 = 1/16