Question

What is the minimum or maximum of `g(x)=-x^2-6x+1`?

Answer 1

What is the min or max of `g(x) = -x^2 - 6x + 1`

Ans Max at vertex (-3, 10)

Explanation:

Since a < 0, the parabola opens downward, there is a Max.at vertex.
x-coordinate of vertex: `x = -b/(2a) = 6/-2 = -3`
y-coordinate of vertex: y = g(-3) = -9 + 18 + 1 = 10