What is the molar mass of $Fe_3(PO_4)_2$ ?

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Answer 1 · 2015-12-18T03:09:03

$357.475"g/mol"$

Take the sum of the molar masses of each individual element.

There are:

$3$ $"Fe"$ atoms
$2$ $"P"$ atoms
$8$ $"O"$ atoms

Notice that the term outside the parentheses can be multiplied into the parentheses to show how many atoms there are of each element in the compound.

$3xx"molar mass of Fe"=3xx55.845"g/mol"=167.535"g/mol"$

$2xx"molar mass of P"=2xx30.974"g/mol"=61.948"g/mol"$

$8xx"molar mass of O"=8xx15.999"g/mol"=127.992"g/mol"$

The sum of the individual molar masses is

$color(red)(357.475)" g/mol"$

What is the molar mass of Fe_3(PO_4)_2Fe_3(PO_4)_2?