What is the molarity of 10.0 g of $KCI$ in 0.500 L of solution?

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Answer 1 · 2016-09-09T06:32:16

$"Molarity"$ $approx 0.25*mol*L^-1$ with respect to potassium chloride.

$"Molarity"$ $=$ $"Moles of solute"/"Volume of solution"$

$=$ $(10.0*g)/(74.55*g*mol^-1)xx1/(0.500*L)$ $=$ $??*mol*L^-1.$

What is the molarity of 10.0 g of KCIKCI in 0.500 L of solution?