What is the molarity of 416.48 g $BaCl_2$ dissolved in $2$ $L$ of water?

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Answer 1 · 2016-04-11T05:42:02

1 mol / L

Molarity = # of moles of solute/ Volume of solution in ( liter)

Number of moles of Ba $Cl_2$ =
mass of Ba $Cl_2$ dissolved/ molar mass of Ba $Cl_2$

mass of Ba $Cl_2$ dissolved = 416.48 g

molar mass of Ba $Cl_2$ = 208.23 g/mol

Number of moles of Ba $Cl_2$ = 416.48 g / 208.23 g /mol = 2 mol

Molarity = # of moles of solute/ Volume of solution in ( liter)

           =   2 moles / 2 L

           = 1 mol /L

What is the molarity of 416.48 g BaCl_2BaCl_2 dissolved in 22 LL of water?