What is the molarity of .450 mol of $NaOH$ in 1.65 L of solution?

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Answer 1 · 2016-05-08T06:31:16

$"Concentration"="Moles of solute"/"Volume of solution"$

$"Concentration"=(0.450*mol)/(1.65*L)$ $~=$ $0.3*mol*L^-1$ with respect to sodium hydroxide. What is the $pH$ of this solution?

What is the molarity of .450 mol of NaOHNaOH in 1.65 L of solution?