Question

What is the molarity of a solution with 6 g of `NaOH` in enough water to make a 2 L solution?

Answer 1

`"Molarity"` `=` `"Moles of solute (moles)"/"Volume of solution (L) "`

Here, approx. `0.05*mol*L^-1`.

Explanation:

And thus,

`"Concentration (NaOH)"` `=` `(6*g)/(58.44*g*mol^-1)xx1/(2*L)` `=` `??mol*L^-1`.