What is the molarity of NO_3^- in each solution?

0.150 M KNO_3
0.150 M Al(NO_3)_3

1 Answer
anor277
Nov 9, 2016

For "potassium nitrate", clearly [NO_3^-]=0.150*mol*L^-1........

Explanation:

For "aluminum nitrate", clearly [NO_3^-]=3xx0.150*mol*L^-1=0.450*mol*L^-1........because "aluminum nitrate" ionizes to give 3 equiv of nitrate anion.

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