What is the norm of $< 7 , -2, -1 >$ ?

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Answer 1 · 2016-08-02T20:38:58

$||A||=3sqrt 6" unit"$

$A= <7,-2,-1>$

$||A||=sqrt(7^2+(-2)^2+(-1)^2)$

$|A||=sqrt(49+4+1)$

$||A||=sqrt54$

$||A||=sqrt(9*6)$

$||A||=3sqrt 6" unit"$

What is the norm of < 7 , -2, -1 >< 7 , -2, -1 >?