What is the polar form of $( -1,16 )$ ?

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Answer 1 · 2018-05-06T17:50:54

the polar cordinates $(r,theta)=(sqrt257,-1.5084)$

the point $( -1,16 )$

$r=sqrt(x^2+y^2)=sqrt[(-1)^2+(16)^2]=sqrt257$

$tantheta=y/x=16/-1=-16$

we will take arctan to each side

$arctan(tantheta)=arctan(-16)$

$theta=arctan(-16)$

$theta=-1.5084$

the polar cordinates $(r,theta)=(sqrt257,-1.5084)$

What is the polar form of ( -1,16 )( -1,16 )?