Question

What is the polar form of `(-1,18)`?

Answer 1

`(sqrt325,93.18^@)`

Explanation:

we know,
`r=sqrt(x^2+y^2)`

`=sqrt((-1)^2+18^2)`

`=sqrt325`

`theta=180^@+tan^(-1)(18/(-1))`

`=180^@-86.82^@`

`=93.18^@`