What is the polar form of $( -1,3 )$ ?

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Answer 1 · 2015-12-08T19:59:44

Polar form is $(r,theta)$

$r=sqrt((-1)^2+(3)^2)=sqrt10$

The point is in quadrant II ...

reference angle $=tan^-1(3/1)=71.565^o$

$theta=180-71.565=108.435^o$

polar form $=(sqrt(10),108.435^o)$

hope that helped

What is the polar form of ( -1,3 )( -1,3 )?