What is the polar form of $( 10,10 )$ ?

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Answer 1 · 2016-02-20T01:15:54

Use the following formulas:

$r=sqrt(x^2+y^2)$

$theta=tan^-1(y/x)$

The rectangular coordinate $(10,10)$ lies in quadrant I. So, $theta$ must fall between $0$ and $90$ degrees

First, solve for r:

$r=sqrt(x^2+y^2)=sqrt(10^2+10^2)=sqrt(2xx100)=10sqrt2$

Now, find $theta$ ...

$theta=tan^-1(y/x)=tan^-1(10/10)=tan^-1(1)=45^o$ or $(pi)/4$

Polar Form : $(r,theta)=(10sqrt2,(pi)/4)$

hope that helped

What is the polar form of ( 10,10 )( 10,10 )?