What is the polar form of ( 11,55 )(11,55)?

1 Answer
Alan P.
Nov 17, 2016

Rectangular (x,y)=(11,55) rarr(x,y)=(11,55)→ Polar: (r,theta)~~(56.09,78.69^circ)(r,θ)≈(56.09,78.69∘)

Explanation:

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tan(theta)="opposite"/"adjacent" rarr theta = "arctan"("opposite"/"adjacent")tan(θ)=oppositeadjacent→θ=arctan(oppositeadjacent)

theta = "arctan"(55/11)="arctan"(5)~~1.3734 ("radians) or 78.69^circθ=arctan(5511)=arctan(5)≈1.3734(radians)or78.69∘

By Pythagorean Theorem:
r=sqrt(11^2+55^2)~~56.09r=√112+552≈56.09

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