What is the polar form of $(11, - 9)$ $( 11,-9 )$ ?

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What is the polar form of $(11, - 9)$ $( 11,-9 )$ ?

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Answer 1 · 2018-03-22T13:35:03

The polar form of the coordinate pair $(11, - 9)$ $(11, -9)$ is $(\sqrt{202}, - 39.289)$ $(sqrt(202), -39.289)$ .

Explanation:

The polar form of a coordinate pair $(x, y)$ $(x, y)$ is $(r, θ)$ $(r, theta)$ .
To find r, we use the formula $r^{2} = x^{2} + y^{2}$ $r^2 = x^2+y^2$ .
$r^{2} = 11^{2} + {(- 9)}^{2}$ $r^2 = 11^2 + (-9)^2$
$r^{2} = 121 + 81$ $r^2 = 121 + 81$
$r^{2} = 202$ $r^2 = 202$
$r = \sqrt{202}$ $r = sqrt(202)$
$r \approx 14.21$ $r ~~ 14.21$
To find $θ$ $theta$ , we use the formula $\frac{y}{x} = tan (θ)$ $y/x = tan(theta)$ .
$\frac{- 9}{11} = tan (θ)$ $(-9)/11 = tan(theta)$
$θ = {tan}^{- 1} (\frac{- 9}{11})$ $theta = tan^-1((-9)/11)$
$θ \approx {tan}^{- 1} (0.818182)$ $theta ~~ tan^-1(0.818182)$
$θ \approx - 39.289407$ $theta ~~ -39.289407$

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What is the polar form of $(11, - 9)$ $( 11,-9 )$ ?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

What is the polar form of (11,−9)( 11,-9 )?

1 Answer

Explanation:

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Impact of this question

What is the polar form of $(11, - 9)$ $( 11,-9 )$ ?