What is the polar form of $(11, - 99)$ $( 11,-99 )$ ?

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Answer 1 · 2018-06-01T22:11:41

Polar:
Exact: $(11 \sqrt{82}, {tan}^{- 1} (- 9))$ $(11sqrt(82), tan^-1(-9))$
About: #(99.61, -1.46)

Cartesian form: $(x, y)$ $(x,y)$

Polar form: $(r, θ)$ $(r, theta)$

$r = \sqrt{x^{2} + y^{2}}$ $r = sqrt(x^2+y^2)$

$r = \sqrt{11^{2} + 99^{2}} = 11 \sqrt{82} \approx 99.61$ $r = sqrt(11^2+99^2) = 11sqrt(82)~~99.61$

$θ = {tan}^{- 1} (\frac{y}{x})$ $theta = tan^-1(y/x)$

$θ = {tan}^{- 1} (- \frac{99}{11})$ $theta = tan^-1(-99/11)$

$θ = {tan}^{- 1} (- 9) \approx - 1.46$ $theta = tan^-1(-9) ~~ -1.46$

Exact

What is the polar form of (11,−99)( 11,-99 )?