What is the polar form of $( 13,1 )$ ?

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Answer 1 · 2018-03-22T09:34:09

$(sqrt(170),tan^-1(1/13))-=(13.0,0.0768^c)$

For a given set of coordinates $(x,y)$ , $(x,y)->(rcostheta,rsintheta)$

$r=sqrt(x^2+y^2)$
$theta=tan^-1(y/x)$

$r=sqrt(13^2+1^2)=sqrt(169+1)=sqrt(170)=13.0$
$theta=tan^-1(1/13)=0.0768^c$

$(13,1)->(sqrt(170),tan^-1(1/13))-=(13.0,0.0768^c)$

What is the polar form of ( 13,1 )( 13,1 )?