What is the polar form of $( 16,0 )$ ?

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Answer 1 · 2015-12-06T00:42:42

rectangular form: $(x,y)= (16,0)$
polar form: $(r,theta) = (16,0)$

$(16,0)$ in rectangular form is a point $16$ units away from (and to the right of) the origin.
So the radius is $r=16$ .

$(16,0)$ lies on the X-axis (so the angle between the line connecting it to the origin and the X-axis is 0).
So the angle $theta=0$ .

What is the polar form of ( 16,0 )( 16,0 )?