What is the polar form of ( -18,-61 )?

1 Answer
Jan 14, 2018

=> color(red)( (sqrt(4045) , tan^(-1) (61/18) + pi ) " In radians"

=> color(red)( (sqrt(4045) , tan^(-1) (61/18) + 180^circ) " In degrees"

Explanation:

We must first use our knowledge of polar coordinates...

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We see from this diagram, that:

color(red)(x = rcostheta

color(red)(y = rsintheta

color(red)( r^2 = r^2cos^2x + r^2 sin^2x = x^2 + y^2 " Using pythagerous"

=> (x,y) -= (rcostheta , rsintheta )

So we can find r:

r^2 = (-18)^2 + (-61)^2

=> r^2 = 324 + 3721 = 4045

=> r = sqrt(4045)

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We can now find alpha

=> tanalpha = 61/18

=> alpha = tan^(-1) (61/18)

Now we need the angle form the positive x axis

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So hence

theta =alpha + pi " Radians"

theta = alpha + 180^circ " Degrees"

=> theta = tan^(-1) ( 61/18) + pi

or => theta = tan^(-1) (61/18) + 180^circ

=> color(red)( (sqrt(4045) , tan^(-1) (61/18) + pi ) " In radians"

=> color(red)( (sqrt(4045) , tan^(-1) (61/18) + 180^circ) " In degrees"