What is the polar form of $( 216,-6 )$ ?

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Answer 1 · 2017-12-21T15:36:47

$( 6sqrt(1296) , 0.028 )$

Using:

Cartesian $( x , y)->$ Polar $-> ( r , theta )$

$r = sqrt(x^2+y^2)$

$theta=arctan(y/x)$

$r=sqrt((216)^2+(-6)^2)=sqrt(46692)=6sqrt(1296)$

$theta = arctan(-6/216)=arctan(-1/36)=0.028$ ( 3 .d.p)

$:.$

$( 6sqrt(1296) , 0.028 )$

What is the polar form of ( 216,-6 )( 216,-6 )?