What is the polar form of $(23, 3)$ $( 23,3 )$ ?

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Answer 1 · 2018-06-05T14:18:12

Polar Form: $(\sqrt{538}, tan (\frac{3}{23}))$ $(sqrt(538), tan(3/23))$

Cartesian Form: $(x, y) = (23, 3)$ $(x, y) = (23,3)$

Polar Form: #(r, theta)

$r = \sqrt{x^{2} + y^{2}} = \sqrt{23^{2} + 3^{2}} = \sqrt{538}$ $r = sqrt(x^2+y^2)=sqrt(23^2+3^2)=sqrt(538)$

$θ = tan (\frac{y}{x}) = tan (\frac{3}{23})$ $theta = tan(y/x) = tan(3/23)$

Polar Form: $(\sqrt{538}, tan (\frac{3}{23}))$ $(sqrt(538), tan(3/23))$

What is the polar form of (23,3)( 23,3 )?