What is the polar form of $(24, 2)$ $( 24,2 )$ ?

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Answer 1 · 2017-08-22T15:24:13

$(24, 2) \to (\sqrt{580}, 0.083)$ $(24,2) to (sqrt580,0.083)$

Convert $(24, 2) \to (r, θ)$ $(24,2) to (r,theta)$

$r = \sqrt{24^{2} + 2^{2}}$ $r = sqrt(24^2+2^2)$

$r = \sqrt{580}$ $r = sqrt(580)$

$θ = {tan}^{- 1} (\frac{2}{24})$ $theta = tan^-1(2/24)$

$θ \approx 0.083 rad$ $theta ~~ 0.083" rad"$

What is the polar form of (24,2)( 24,2 )?