What is the polar form of ( 25,16 )?
1 Answer
Feb 15, 2016
(sqrt881 , 0.57 )
Explanation:
using the formulae that links Cartesian to Polar coordinates.
• r^2 = x^2 + y^2
• theta = tan^-1(y/x) here x = 25 and y = 16
hence
r^2 = 25^2 + 16^2 = 881 rArr r = sqrt881 and
theta = tan^-1(16/25) = 0.57 "radians"