What is the polar form of ( -27,15 )?
1 Answer
Jan 23, 2016
( sqrt954 , 2.63 )
Explanation:
Use the following formulae that links Cartesian to Polar coordinates.
• r^2 = x^2 + y^2
• theta = tan^-1 (y/x) Here x = - 27 and y = 15 .[ Note also that (-27 , 15 ) is a point in
the 2nd quadrant and so care must be taken to ensure
theta is in the 2nd quadrant.]
r^2 = (-27)^2 + (15)^2 = 729 + 225 = 954
rArr r = sqrt954
theta = tan^-1 (15/-27) =- 0.51 color(black)("radians") To find
theta color(black)(" in the 2nd quadrant")
theta = ( pi - 0.51 ) =2.63 color(black)(" radians")
.