What is the polar form of $(3, 27)$ $( 3,27 )$ ?

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Answer 1 · 2017-04-04T07:58:43

$= (3 \sqrt{82}, {83.66}^{\circ})$ $= (3 sqrt82, 83.66^@)$

Polar form $= (r, θ)$ $=(r, theta)$

$r = \sqrt{3^{3} + 27^{2}} = \sqrt{9 + 729} = \sqrt{738} = 3 \sqrt{82}$ $r = sqrt(3^3 + 27^2) = sqrt ( 9 + 729) = sqrt 738 = 3 sqrt82$

$tan θ = \frac{27}{3} = 9$ $tan theta = 27/3 = 9$
$θ = {tan}^{- 1} 9 = {83.66}^{\circ}$ $theta = tan^(-1) 9 = 83.66^@$

Polar cordinate $= (3 \sqrt{82}, {83.66}^{\circ})$ $= (3 sqrt82, 83.66^@)$

What is the polar form of ( 3,27 )(3,27)( 3,27 )?