What is the polar form of $(-3,3)$ ?

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Answer 1 · 2016-10-16T19:00:25

From Cartesian form to polar form:

$(-3,3)-> (3sqrt(2), (3pi)/4)$

Because the x coordinate is negative, one must add $pi$ to the inverse tangent function to obtain the correct angular component:

$theta = tan^-1(3/-3) + pi$

$theta = (3pi)/4$

The radial component is:

$r = sqrt((-3)^2 + 3^2)$

$r = sqrt(18) = 3sqrt(2)$

What is the polar form of (-3,3)(-3,3)?