What is the polar form of $( 36,48 )$ ?

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Answer 1 · 2016-09-10T09:31:18

Polar form of $(36,48)$ is $(60,53.13^o)$

Polar coordinates $(r,theta)$ are related to Cartesian coordinates $(x,y)$ by the following:

$x=rcostheta$ , $y=rsintheta$ and $r^2=x^2+y^2$

Hence, let polar coordinates of $(36,48)$ be $(r,theta)$

Hence $r=sqrt(36^2+48^2)=sqrt(1296+2304)=sqrt3600=60$

$costheta=36/60=0.60$ and $sintheta=48/60=0.80$

and from tables $theta=53.13^o$

Hence, polar form of $(36,48)$ is $(60,53.13^o)$

What is the polar form of ( 36,48 )( 36,48 )?