What is the polar form of $( -4,6 )$ ?

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Answer 1 · 2017-10-18T22:14:23

$(-4,6)=(2sqrt13,-0.923)$

For any point $P(a,b)$ in the Cartesian plane, we can convert it to polar form $(r, vartheta)$ using the following formulae

$r=sqrt(a^2+b^2)$

$vartheta=arctan(b/a)$

$thereforer=sqrt(-4^2+6^2)=2sqrt13$ and $vartheta=arctan(-4/6)=-0.923$

$therefore(-4,6)=(2sqrt13,-0.923)$

What is the polar form of ( -4,6 )( -4,6 )?