What is the polar form of $( 5,9 )$ ?

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Answer 1 · 2016-01-13T14:55:58

$( sqrt106 , 1.06 )$

To convert from cartesian (x , y ) to polar ( $r , theta )$

use the following relationships :

$r^2 = x^2 + y^2 rArr r = sqrt(x^2 + y^2 ) , theta = tan^-1(y/x )$

using (5 , 9 ):

$r = sqrt(5^2 + 9^2 ) = sqrt(25 + 81) = sqrt106$

and $theta = tan^-1(9/5) = 1.06$

$rArr (5 , 9 ) → ( sqrt106 , 1.06 )$

What is the polar form of ( 5,9 )( 5,9 )?