What is the polar form of $( 8,3 )$ ?

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Answer 1 · 2016-01-14T20:07:55

$(sqrt73 , 0.36 )$

Making use of the formulae that links Cartesian to Polar coordinates.

$r^2 = x^2 + y^2 and theta = tan^-1(y/x )$

For (8 , 3 ) : $r^2= 8^2 + 3^2 = 64 + 9 = 73 rArr r = sqrt73$

and $theta = tan^-1(3/8 ) ≈ 0.36 radians$

What is the polar form of ( 8,3 )( 8,3 )?