What is the projection of (-i + j + k) onto ( i - j + k)?

1 Answer

The projection of a vector a onto vector b is given by

proj_a b=(a*b)/absa^2 *a

Hence

The dot product of a=(-1,1,1) and b=(1,-1,1) is

a*b=-1-1+1=-1

The magnitude of a is absa=sqrt(-1^2+1^2+1^2)=sqrt3

Hence the projection is

proj_a b=-1/3*(-1,1,1)=(-1/3,1/3,1/3)=1/3*(-i+j+k)